X^2+56x=177

Solution for X^2+56x=177 equation:

X^2+56X=177

We move all terms to the left:

X^2+56X-(177)=0

a = 1; b = 56; c = -177;
Δ = b2-4ac
Δ = 562-4·1·(-177)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-62}{2*1}=\frac{-118}{2}
=-59
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+62}{2*1}=\frac{6}{2}
=3
$